I shall try and highlight an area which is
- Easier to implement
- Less code
- More efficient
#define SQUARE(x) ((x)*(x))
float Length(CVector3* p_pvOne, CVector3* p_pvTwo)
{
return (float)(sqrt(SQUARE(pvTwo->X - p_pvOne->X) + SQUARE(pvTwo->Y - p_pvOne->Y) + SQUARE(pvTwo->Z - p_pvOne->Z)));
}
(The sqrt function has been traditionally considered slow and avoided if possible. I am unsure of its performance on modern hardware however the above could be optimised by not calculating the sqrt in the length function, and comparing it to the expected value squared.)
An better optimisation is to remove the requirement for calculating the distance from each patch to the centre of LOD completely. Instead of using the distance from the centre, I now recursively step from the centre to each neighbour, then onto each of their neighbours while incrementing the 'distance' with each step. When the 'distance' reaches a predefined value, the edge of the LOD area has been reached. In the following images 'distance limit' is set to 3.
The results above are not as desired. Some analysis showed that the east and west neighbours of the centre of LOD are within 3 recursive steps from the north neighbour (which is processed first). Because of this the east and west patches are marked as processed and will not be processed again when directly updated from the centre patch.
To overcome this, when processing a patch, if it is already flagged as processed, I compare its distance in steps from the centre of LOD. If the current distance is less than the stored distance I process again. Reading that sounds a little confusing so I shall try and explain in some steps. (only key steps are listed)
- Move from the centre patch to the north. Its distance is stored as 1
- Move from the current patch (north) to the east. Distance is stored as 2
- Move from the current patch (north->east) to the south (this is the centres east neighbour). Distance is stored as 3.
- Move from the centre patch to the east. This patch is flagged as processed at a distance of 3. The current distance is 1 therefore ignore previous processing and process again.
That looks better. It is a uniform area around the centre of LOD. However, it is still not correct. To render the next area of lower LOD I step 1 level up the patch tree and render outwards from here. Patches are not rendered if any of its children have been rendered as this would cause an unacceptable overlap and possible onscreen artifacts. This results in huge holes in the terrain.
The above example has resulted in code which is smaller, simpler to understand and faster to run than the previous version based on actual distance.
Planet rendered from orbit showing LOD |
Same planet rendered from atmosphere, again showing LOD |
Great work! Did I miss a download link? I cant seem to find any engine download links..
ReplyDeleteHey, nice blog, could I possibly get your email address? If possible I'd like to ask how you calculate neighbours, I'm sure that you could give me a guide which would prevent wasted time.
ReplyDeleteHi
ReplyDeleteI am contactable on decadeengine@hotmail.com, by email or instant messenger.
Ciaran